Matter routinely falling to Earth; how much heat released?

I expect I could research the relevant facts, figures and formulae to try to work this one out myself, but a)I’d be forever unsure I was anywhere near correct and b)I’m too damn lazy.

OK, so I understand that objects falling from high places to low ones experience a change in potential energy and that the balance of this is released as heat (I learned that from rebuttals to the creationist vapour canopy hypothesis).
I also understand that matter is constantly falling to Earth from space in the form of meteorites and dust.

So… how much heat is imparted to the Earth(incl the atmosphere) by a day’s worth of typical space dust/meteorites? Bonus points will be awarded if this can be expressed in terms of approximately what volume of water could be raised from 20C to boiling.

Assuming 100 metric tons of dust per day, falling from 100 km, I get 98 GJ or 23 Gcal.

This is totally insignificant when compared to the energy provided by the mean solar flux.

Thanks for the info. So I think that is equivalent to the energy required to boil 1,225,000 litres of water (from 20C at standard pressure).

But the average atmospheric entry speed of meteoric material is about 22 km/sec. That beggars the energy from a 100 km fall.

I agree, 100km fall is not a good approximation because the material is essentially falling from infinite distance.

But still, 100 tons falling at 22 km/s releases only 2.4x10[sup]13[/sup] joules. If you get that much per day, that’s a rate of 280 MW. About the same as sunlight falling on a 50-acre surface.