Smoke Detector Radiation Danger

I was reading the editorial section of today’s paper (New Zealand Sunday Star Times) and I came across a letter about the use of radioactive material in smoke detectors.
The letter had an almost conspiricy theory tone about, with a claim that information about smoke detectos was "being withheld from the public world-wide.
I was aware that very small quantities of Americium were used in most smoke detectors, but this letter implied (without actually saying, mind you) that this was dangerous and quoted that an (unnamed) test of 200 smoke detectors had shown that “all emmited between 300-400 counts of radition per second”
Now, I don’t have a clue as to how to interpret that figure, so two questions.

  1. What does that mean?
  2. How dangerous is that much radiation?

From here

From the American EPA site.

It seems you stand more risk if you tamper with the detector, and actually swallow or inhale Americium, than anything else.

“Counts per second” is the number of photons detector by an instrument every second. Unless they tell you the size and efficiency of the detector as well as the distance from the source, it’s a meaningless number.

The Master speaks.

Whoops. Should have referred to what This Guy had to say.

Wow, thanks for the quick and detailed responses.

That should be “detected by”, of course. Sorry…

We handled Alpha-emitting radiation sources all the time in high-school chemistry, with hardly any special equipment. Like Desmostylus said, Alpha rays (aka Helium nuclei) can be completely blocked by a single sheet of paper, and make up most of the radiation in a detector. Gamma rays, although much more dangerous, are emitted in such low quantity as to be negligible compared to background radiation. Even if you were to remove the radioactive source, I think your dosage would still be negligible, unless you decided to sleep with it close to your head on a regular basis or something :slight_smile: