So old, can any one remember?

Three guys go to a hotel and rent a room. The guy says the room is $30. They each give him $10 and go to their room. A few minutes later the guy discovers that the room he rented them is only $25. He gives the bell-hop $5 and tells him to return it to the guys in the room. On the way there the bell-hop can’t figure out how to divide the $5 between 3 guys, so he gives them each $1 and keeps the other $2. So they only paid $9 each for the room, which comes to $27. The bell-hop kept $2, that’s $29 … where did the other dollar go ???


poppy <<<<<< feelin’ so stupid right now.

:rolleyes:

You’re counting the wrong numbers. The $2 the bellhop kept is part of the $9 each paid, and then you’re adding it on again at the end instead of the $3 refund.

A = Final cost($25)
B = Amount that bellhop kept ($2)
C = Amount refunded to men ($3)

so A + B + C = 30

But your statement is saying:
(A + B) + B = 29

Get it?

If not, maybe Cecil can explain it better.

You are counting some money twice when you say:

“So they only paid $9 each for the room, which comes to $27. The bell-hop kept $2, that’s $29”

You have already counted the $2 kept by the bell-hop in the cost of the room. You tried to trick us when you said “that’s $29”, sneakily adding the $2 to the $27 that already includes the $2.

Thanks Gunslinger, I see the error of my thinking!
Guess I must be smokin’ too much!

This has come up several times before on the board. Cecil has written a column on it.

Check out The 3 guys, the bellhop, and the missing buck.