The sad part is I took stats around 12 years ago, and even got an ‘A’. But I just can’t remember the formula for determining odds for multiple attempts. Say you flip a coin three times. What are the odds that you will get at least one “heads” and how determine the odds?
Thanks.
Sua
I can’t think of the general way to do this, but it is easier to calculate the odds that you will NOT get at least one heads. You will have to get three tails so that is:
P(t and t and t)
= P(t)*P(t)*P(t)
= 0.5 * 0.5 * 0.5 = 0.125.
At least one heads must be 1 - (NOT at least one heads) so:
P(at least one heads) = 1 - P(t and t and t) = 0.875
Or just think of it visually. The possibilities are
HHH
HHT
HTH
HTT
THH
THT
TTH
TTT
So there are eight equally probable events, one of which has no heads. So the probability is you will get at least one head is 7/8.