What’s the best hand to go heads up against A, A with (besides another A, A)?
What’s the worst hand to go heads up against A, A with?
What are the most lopsided hole cards two players can go heads-up against each other with? Player A has what cards and Player B has what cards to give Player A the biggest advantage possible?
I don’t understand. TH’E isn’t played with the hole cards showing, so the “best” hand one can have against AA (and you have no way of knowing if this is what your opponent holds) is whatever you can convince your opponent you have. If you have a flush, good. If you can make him think you have a flush, equally good.
On the various Hold’Em threads, there no end of bellyaching from people who were holding AA and lost to an unsuited 2-7 when the river ran a certain way.
Then I still don’t understand your question. I suppose the best possible counter to AA would be AK suited, with an eye on getting a royal flush, but that’s overkill. Having any card could, with the right flop, turn and river, clobber AA. A hand of 2,7 off-suit will crush AA if the 3, 4, 5 and 6 of the 2’s suit turn up, creating a straight flush. Heck, even if the 3456 is a rainbow, the straight beats a high pair. A pair of twos (and useless other cards) means three-of-a-kind beats two pairs.
He’s talking about heads-up “races” – no betting, just deal out the board and see who wins. Against AA, which hands have the best and worst odds, and which is the most lopsided matchup possible.
Certainly not, as with AK two of the cards that the underdog could use to make a straight, two pair, or trips are in the opponent’s hand. More likely it would be something like 78 suited.
For “worst hand against AA” I would guess something like A-6 off-suited; the point is that with 2-7, 2-2 or 7-7 appearing beats the pocket AA; with A-6, if the other A appears it doesn’t help, so it’s gotta be 6-6 to beat the A-A with pairs. (Of course this ignores straights and flushes. I guess the 6 should be the same suit as one of the other players As to cancel out flushes too. Straights still favor the A-6, but this is pretty unlikely.)
He’s asking for odds, plain and simple. Do you ever watch poker on TV? They show the odds of two hands against each other pre-flop. Forget about bluffing and betting and all that stuff, he’s just asking percentages.
Here are my wild-ass guesses:
Against AA, two suited connectors (of a different suit than either ace) would seem best. Ax is dominated (even AKs), as is any lower pair. Suited connectors gives you a shot at a flush, a straight, two pair, trips, full boat, etc. Suppose I should specify middle suited connectors, so you can hit the straight on either end.
Worst hand against AA would be, I think, Axo, where x is 6-9, so there’s no straight possibility, and x is same suit as one of opponent’s A’s. 27o against AA actually ain’t that bad, as you’ve got two live cards–something like 25% IIRC.
Most lopsided head’s up? Hmm–I guess it’s not AA against something else or you wouldn’t have asked this as a separate question. That’s a toughie. I’ll have to think about that.
78s (Ace of spades is live) – 22.87% --> This is probably the best.
KK (same suits as the aces) – 17.09%
22 (same suits as the aces) – 16.83%
72o (same suits as the aces) – 10.87%
K2o (same suits as the aces) – 9.64% --> The cards are too far apart to use both in a straight, and getting a 4-card straight either high or low is hampered by the two dead Aces.
A6o (6’s suit is shared by one the aces) – 5.65% --> This is probably about as bad as it gets. Note that A7o (among other, probably) yields the same result.
Well, off the cuff it would seem that it would have to be something that would predispose you to at least a straight, since according to probability you have a less than or equal chance as your opponent of having a pair, 2 pair, or trips, only yours will necessarily be worse.
Since only 2 of 4 aces remain in the deck, it would seem best to have 2 cards that might lead to a straight which wouldn’t include an ace.
It actually wouldn’t matter terribly much which straight in particular (e.g. 3, 4, 5, 6, 7 or 8, 9, 10, J, Q) since they’ll both beat a pair of aces equally.
If your cards are suited now you’ve included the possibility of a flush. So my off-the-cuff guess to your question would be suited connectors with 8, 9 being the highest you’d want.
Ah, sorry. The “s” signifies that the hand is suited, not necessarily that those are the 7 and 8 of spades. What I meant is that the 22.87% assumes that the ace of that particular suit is not in the opponent’s hand. Which was probably obvious anyway.
Okay, think I’ve got the third one. KK against K2 (w/ 2 same suit as one of the kings) gets a serious ass kicking of 94%-4%. Can’t imagine much worse than that.
Okay, gotcha. The most lopsided match I can make using this handy-dandy calculator is AA vs A9, with the 9 matching suits with one of opponent’s aces, at 5.9% for the underdog. Why the odds are lower than A2 escapes me.
Better than 78s? I’m skeptical. It’s not a pair. It’s hard to imagine that it wouldn’t be a suited connector, and the further away from 78s the connectors get, the worse the odds become.
56s shows another tenth of a percent. Not sure why, though – I’d figure that killing off one of the AA guy’s straight possibilities would be overwhelmed by killing off two of your own.