the wavelength of a baseball?

It’s either extremely large or extremely small. I have just forgotten which it is and why. Please refresh my memory.

thanks,
eric

Extremely long.

How long? Kilometers? Megameters?

Actually, extremly short.

The de Broglie wavelength of a baseball move at a speed of 10 m/s is around 10^-25 Angstrom governed by the de Broglie relation:

Wavelength = h/p where h is Planck’s constant and p is the momentum of the particle. For an electon accelerated through 100 volts this is around 1 Angstrom.

From here: http://learn.chem.vt.edu/tutorials/atomic/debroglie.html

Not sure what you are asking here, but I’ll give it a shot.

Ballistic trajectories aren’t really waves per se, but if you are assuming that the ballistic arc of a pitch in major league baseball is the upper half of a single sine wave cycle, then the wavelength would be 120 ft (37 m), or the distance from the pitchers mound to home plate (60ft) times 2. Since this is dependant on the distance of the trajectory, the wavelength would of course be different for a hit, a play to first, etc.

However, you may not mean that. If you are asking what is the particle wavelength of a baseball, then it would be very, very small. Because wavelength is inversely proportional to mass (wavelength = h/m*v), macroscopic objects have extremely small wavelengths

h=planck constant (6.62610-34 Js)
m=mass
v=velocity

Hmmm, I guess I was wrong. I was pretty sure it was the other way around.

Hmmm, I guess I was wrong. I was pretty sure it was the other way around.