[QUOTE=gazpacho]
Gas contains roughly 1.3 * 10^8 Joules
An internal combustion engine is about 25% efficient.
This means for a 25MPG it takes about 1.3 * 10^6 joules to go a mile.
There are 3.6 * 10^6 joules in a kilowatt hour.
Where I live the cost of electricity is roughly 14 cents a kilowatt hour.
Battery charging is about 66% efficient for nickel metal hydride batteries. This number seems to vary a lot based on quick internet scans.
Electric motors are about 85% efficient. So 2.3 * 10^6 joules are needed to go a mile.
So about 9 cents a mile. Or about 11 miles per dollar.
[/QUOTE]
You missed something. In a gasoline engine, all of the energy lost to braking is dissipated as heat. In an electric car regenerative braking gets a lot of that back. A 2000 pound car traveling 30 miles per hour loses 2.6 * 10^6 joules to stop. Even if you only get 40% of that back, it’s going to be a significant factor, depending on your driving habits.
That 2.6 * 10^6 joules seems high to me, it’s enough energy to drive two miles, but when I consider how much gas I use going from 0 to 30, compared with how much I use cruising at a fixed speed, I guess it makes sense. I’m sure one of you guys will check my math.
Of course, you could use regenerative braking in an internal combustion engine too, but you’d need a battery to store it, and an electric motor to utilize it, and next thing you know you’re driving a freakin hybrid and you’ve got to pretend you like Ed Begley Jr., and who needs that?