I’m always uncomfortable with explanations like “it’s a physics thing,” but here’s my best guess at the reasons behind the effect reported by Mtgman.
If the float in the tank is actually mounted on a pivot near the top of the tank (like this one), then what amounts to be a cosine (or is it sine?) error will be injected in the process. I say “if” because I don’t know if that schematic really depicts a typical float setup or not.
In that schematic, it appears that the resistance change in the potentiometer is proportional to the change of angle of the float rod - call this angle q. Say q = 0 when the tank is full and increases as the level drops.
Let’s assume for now that then tank is a perfectly uniform box, and thus that the surface height above the bottom exactly reflects the volume of fuel remaining. Suppose for our purposes that the depth of the tank and the length of the float rod are both H. h starts out a zero, and increases to H as the tank empties.
We don’t really want to know q - what we want is h, the distance from the top of the tank to the surface of the fuel. However, q is much easier to measure so we’ll measure that and relate it to h.
A little trig shows that h = Hsinq. Here lies the source of the problem.
The rate at which q and h change with fuel consumption are different: dh = Hcosq dq. In other words, a given change in h will cause a change in q that is proportional to cosq.
When h (and q) are both about zero, the relationship is close to linear. However, as the fuel level drops and q goes up, a given change in h will result in a much larger change in q than it did before. IOW, the float rod angle will start dropping faster as the tank goes down.
Unless this was compensated for (which they probably don’t bother to do), this would result in the first “half” of the tank as indicated to last much longer than the second “half.” The gage would read half-full when q = 45[sup]o[/sup]. However, that would occur when h = 0.707H = far lower than half-full. You’d use 70% of your fuel getting to the half-way mark, and have only 30% left at that point.
I don’t know for sure if this is what’s going on, but it sounds reasonable to me. Also, I did work with perhaps overly-simplified geometry, which may be why these numbers sound quite a bit worse than one commonly experiences.