x - 1 = y^(1/3) Solve for y

It’s a problem from a pre-calc class I am taking voluntarily. A little help, please.

Think natural logs (ln) and e

(dusting off the ol’ brain)

maybe:

y = (x-1)^3

Chris S

y = (x-1)[sup]3[/sup]

No free homework answers here…but here’s a little help, anyway:

When a number is raised to a power, the exponents multiply, i.e. (x[sup]n[/sup]}[sup]2[/sup] = x[sup]2n[/sup]
Generally, any number is itself to the first power, so your equation is equivalent to:

(x-1)[sup]1[/sup] = y[sup]1/3[/sup]

Does that suggest a solution? If not, I’ll try again.

Tsk, tsk–it’s better to help people solve math problems themselves than to give them the answers, guys–it helps the learning process.

As for you, Finch–you’re just evil. I like that.

I figured that any class would require one to explain why an answer is the right one; that’s why I felt OK giving away the answer.

Hmmm…OK, I just prefer leading people to answers. Different approach.

Oh, it’s obvious. I had it in my head that I somehow had to divide x - 1 by 1/3. Perhaps the medication needs adjusting again.