No, this is not my homework.

Two six-sided dice are rolled (they have the standard values).

The number of the first dice is multiplied by the number of the second. So if a 2 and a 5 are rolled, the result is 10.

Possible results:

1,2,3,5,6,8,9,10,1215,16,18,20,24,25,30,36

If a number has already been rolled, then the next “unrolled” number is used. The numbers 1, 9, 10, 12, 15, 16, 18, 20, 24, 25, 30 have already been rolled.

The way I see it the chances of the remaining numbers look like this. We are 3 people who rekon this looks right, but I thought that who knows better than the dopers I am still in pain from trying to follow the discussion of the NY lottery results that time.

36 = 56%

5 = 14%

6 = 11%

2 = 7%

3 = 7%

8 = 6%

That look right to you guys?