If you know Vbe and Vce how do you find Vcb? Isn’t Vce=Vbe-Vcb?
Common emitter, Forward Active by the way.
Thanks!
If by “Vbe”, “Vce”, and “Vcb” you mean the actual voltages(*) between base and emitter, etc., for a given transistor state, then Vce=Vbe+Vcb. (Remember that Vce=Vc-Ve, where Vc and Ve are the collector and emitter voltages relative to some arbitrary fixed reference. So Vbe+Vcb=(Vb-Ve)+(Vc-Vb)=Vc-Ve=Vce.) This doesn’t depend on what kind of transistor you have, though of course the likely values of these voltages does.
(*) I just say this to make sure you’re not using tabulated values like the Vce saturation voltage in this calculation; not all of the tabulated values refer to the same transistor state.