My wife and I are fans of the show Deal or No Deal (yeah, live with it).
I’m interested in strategy in the game and the probabilities involved.
For those unfamiliar:
The game features 26 suitcases, each containing one of the following monetary values:
$.01
1
5
10
25
50
75
100
200
300
400
500
750
1,000
5,000
10,000
25,000
50,000
75,000
100,000
200,000
300,000
400,000
500,000
750,000
1,000,000
I pick a case to hold onto, unopened, and then open up the other cases one by one, revealing which prize I didn’t win. At certain points, the “banker” who is paying out whatever amount I finally end up with makes me an offer to buy me out of the game.
The amounts are randomized among the cases, and neither I nor the banker knows what’s in each case at the beginning.
Since they are random, I will not confuse the issue by randomly choosing numbered cases. I choose case #1 to hold onto.
Round 1: I must open 6 cases, so I’ll just go in numerical order.
#2 - 75,000
3 - 100
4 - 400,000
5 - 400
6 - 500
7 - 5,000
So I don’t have any of those amounts in my case. The banker now makes me an offer to buy my case and walk away from whatever amount might be in there.
The offer is $28,064.
The remaining possible amounts left to be revealed are:
$.01
1
5
10
25
50
75
200
300
750
1,000
10,000
25,000
50,000
100,000
200,000
300,000
500,000
750,000
1,000,000
I must open five more cases before another offer is pending.
My question: what is the probability that I will:
a) beat the banker’s offer?
b) have a dollar value in my case greater than or equal to $100,000?
c) end up holding the $1,000,000 case?
Is it worth it to me to open 5 more cases before hearing another offer, knowing that if I eliminate larger amounts from the board, the offer will drop, but if I eliminate smaller amounts, the offer will go up.
I suspect it is something like the fabled Monty Hall problem, but in that one, Monty knows what’s behind each door. Deal or No Deal’s banker does not.
Well?