Now that I, along with everyone else on the planet, is pretty much cooped up, I’ve been spending some of my “down time” playing billiards on a my cellphone. The game seems to be realistic enough that the [url=]diamond system works for a fair number of my shots on a traditional table, which has nine diamonds along the length of the table and five along the width of the table (including the center point of the pocket for pocket billiards as a diamond). This is the same for any rectangular table, whether the table has pockets or not or the dimensions of the table.
Now, the app has two non-traditional shapes, a round table and a hexagonal table. I have actually seen in real life such tables, so I know they’re not just figments of the app’s designer.
For the round table, there are twenty-four diamonds counting around the table, again counting the six pockets as diamonds for pocket billiards. The twist here (besides the table being round) is that the diamonds are divided equidistantly (is that the correct word?) around the table, with every fourth diamond actually a distinctive mark instead of an actual diamond. The pockets are considered the distinctived mark on pocket tables.
For the hexagonal table, there are the same number of diamonds and the sides of the table are the same length. The diamonds are distributed in the same manner as on the round table.
So, here’s my dilemma. I do not know how to adapt the diamond system to the round and hexagonal tables. As billiards, at its heart, is a game of geometry, there should be a way to figure this out.
Anyone want to give it a shot?