…and typewriter.
oops- newspaper.
golgo13:
Yes, but the last half of the word must also be a synonym for the entire word…what’s a “rine”?
However, you’re right that male/female plays into this. The correct answer to the riddle is bridegroom.
Chaim Mattis Keller
What word starts with C, ends with a T and means the same thing as “pussy”?
I can think of two…
Anyway, here’s my puzzle. The letters of the alphabet are divided into five groups as shown below. What determines which group each letter goes in?
AMTUVWY
BCDEK
HIOX
NSZ
FGJLPQR
I’m now trying to recall the letters.
AUVWYM Group is symetric on a vertical axis.
BCE Group is symetric on a horizontal axis.
NSZ Group is symetric about the center.
QPR Group is not symetric at all.
I’d have more respect for you if only you were more like me.
You forgot to do “HIOX” which are symmetrical on both the horizontal and the vertical axes.
Greg Charles’ answer to the counterfeit coin problem got me thinking.
First the weighings he gives (1,2,3,4 v 9,10,11,12 etc.) lead to 24 different ways the balance ends up. It can drop left (L), balance (‘B’) or drop right (‘R’). So e.g. if the counterfeit coin is no. 1 and light, then the balance would go LLB on the 3 weighings. If no. 1 was heavy it would be RRB.
So far so good. But there are 12 coins and each can be light or heavy = 2x12 = 24 possibilities. There are 3 balance results on each of 3 weigh-ins = 3x3x3 = 27 possibilities.
OK, the unused 3 results are LLL, BBB and RRR. Can we make use of them? How about the problem states that you just suspect one coin may be counterfeit - and if all 3 weigh-ins balance then there is no fake.
That leaves two possible results. So I add one genuine coin and another suspect (the 13th!). The suspect stays on the same side of each weighing, and the genuine on the other.
Have I successfully extended the problem? Was it worth it?
cmkeller, you are correct. I have also seen ‘jaw’ included.