I’ve been researching this, but I still have some questions. I got betrayed by another teacher who said that the hybridization is based on the number of bonds, but I find that it’s the bonds (not counting double or triple bonds) plus the unshared pairs that creates the orbitals: water has sp3 hybridization because of the 2 bonds and the 2 unshared pairs on the oxygen. Right?
I need to know if something like F2 has hybridization because it’s bonding once. I know the unshared pairs want to get away from each other and the bonding pair, but does this mean that it has sp3 hybrids in the valance shell? I can’t find even my college-level book addressing this directly.
Oh dear God, I just found in this book that H2S is thought not to have hybrids, because the bond angles are at 92 degrees, close to 90 degrees, which is not an sp3 hybrid-type angle. It says that unhybridized angles occur in “hydrides of other 6A elements and larger 5A elements.” I guess "larger means “larger than oxygen”? Are they saying that HCl doesn’t have hybrids because Cl is from 6A?