Hi.
My daughter loves scuba diving, and asked me if it would be possible to “filter-out” the dissolved Oxygen in seawater to allow tank-less diving, just like something she saw on the internet. Some further googling as well as some very basic calculations quickly led me to believe that this approach is not practical, and what she saw was a scam.
However, it seems to me that there is a lot of Oxygen locked up in the water molecules themselves, so I wondered why nobody has tried electrolysis to liberate O[sub]2[/sub]. I mean, it’s been demonstrated a million times in science demos for middle-schoolers.
To make things easier, let’s not worry about issues of pressure and electrode efficiency.
Assumptions:
1 liter/breath
40 breaths/min
This gives us (1L/breath) x (40 breaths/minute) x (1 minute/60 seconds)=
0.667 liters of air/second
Air is roughly 20% oxygen (O[sub]2[/sub]), so we will need to generate
(0.667 liters/sec) x (0.2) = 0.133 liters/second of O[sub]2[/sub]
Using the universal gas law to calculate the number of moles of O[sub]2[/sub], I get
N=(PV)/(RT)
= (1 atm x 0.133 liters)/(0.082057 Liter atmosphere mol[sup]-1[/sup] K[sup]-1[/sup]) x 293 K
=5.5 x 10[sup]-3[/sup] moles of O[sub]2[/sub]/sec
Now, we’ll need to reduce two water molecules in order to liberate a molecule of O[sub]2[/sub]. Also, this is a 2-electron process, so we’ll actually need to provide
2.2 x10[sup]-2[/sup] moles of electrons/second
Using Avogadro’s number, this works out to
(2.2 x 10[sup]-2 [/sup]moles) x (6.02 x 10[sup]23[/sup]mole)
= 1.32 x 10[sup]22[/sup] electrons/sec
So far, so good. Let’s convert to coulombs:
(1.32 x 10[sup]22[/sup] electrons/second) x (1 coulomb/6.242 x 10[sup]18[/sup] electrons)
= **2.11 x 10[sup]3[/sup]coulombs/sec. = 2110 Amps **
If my math and reasoning are correct (are they?), I think I know why this approach hasn’t been tried; 2000 amps + seawater is probably a very bad idea.
Any thoughts? Did I miss something?