mnemonic device for converting between Fahrenheit and Celsius

inspired by this column

Cecil wouldn’t have been stumped by the question of where the Celsius and Fahrenheit temperatures coincide if he could just remember that shifting by 18 degrees Fahrenheit is the same as shifting by 10 degrees Celsius.

But for those who don’t want to have to remember the number 18, just remember any two points on the scale and you can work it out. You probably already know one:

0 Celsius = 32 Fahrenheit = freezing

Another easy to remember point is this:
10 Celsius = 50 Fahrenheit

So from that, you can easily see that an 18 degree difference on one scale is 10 degrees on the other.

Hence by a few steps of subtraction:
-10 C = 32-18 F = 14 F
-20 C = 14-18 F = -4 F
-30 C = -4 -18 F = -22 F
-40 C = -22 - 18 F = -40 F

The convenient thing about using 10 C = 50 F as your second point (besides the fact that they’re nice round numbers) is it’s not too far away from most of the temperatures you’re likely to encounter in day-to-day life. You can easily rattle off 20 C = 68 F or 30 C = 86 F

Yes, but where do the scales intersect if we follow Celsius’s original scheme of boiling at 0, and freezing at 100?

And is there a mnemonic?

:smiley:
+12.5

Belay my last. This isn’t right at all.

I screwed up the y intercept. It’s 75.714. Give or take.

Well, you could use:
100 = 32
90 = 50

Proceeding from there . . .
80 = 68
70 = 96

Closing in on it…

75 = 77

Intersect at approximately 76 (more than that I wouldn’t do in my head)

The exact value is 75 5/7.

Guess what I hid in my last post? A small change to the coding, and viola!

ETA: Yes I know it’s really voila. I just like it the other way.

Another question about that column: Why does Cecil refer to him as “old man Fahrenheit”?

He was only 38 years old when he invented the thermometer. That’s not all that ‘old’. Hasn’t Cecil been publishing columns about that long?

When we first went metric in the 1970s the rule of thumb was to take the Celsius temperature, double it, and add 30 to get the approximate equivalent Farenheit temperature.