Need help with a math problem?!?!

I’m thinking about buying a 40 inch widescreen projection tv with a 16:9 aspect ratio.

The question is: When I’m watching standard 4:3 programming, I will have the black bars on the right and left side of the screen(as opposed to the top and bottom when veiwing letterbox format dvd’s on a standard screen), what will be the size of the picture compared to a standard television set. 27"? 32"? Is there a simple formula I could use?

Please help as I figure I’ll be watching standard 4:3 programming for sometime still before the new standard is, well, standardized.

Try this site:

Type in 40 for the widescreen dimension and anything you want for the 4:3 dimension. On the results page, you will see that a 40" widescreen TV is the equivalent of a 32.7" 4:3 set.

Hope this helps.

P. S.: I’m sure you could figure it out with paper and pencil using the Pythagorean Theorem, but who has that kind of time? :wink:

Well, your TV is 40", 16:9 ratio.

16^2 + 9^2 = 337

sqrt(337) = 18.357…

Scale that up to 40, and we get that your TV is 34.86" x 19.61"

So the vertical part of the screen (and image) is 19.61", the horizontal part of the image will be 4/3 of that, or 26.15", so the image is 26.15" x 19.61".

26.15^2 + 19.61^2 = 1068.37, whose square root is 32.69", which is the (diagonal) size of the image.

I reckon I answered your question, too. :smiley: