Nuclear Fusion Question

I’m looking for an explanation of nuclear fusion that might not be so simple. The extent of my knowledge thusfar is that up to a certain point in the periodic table, the sum of the mass of a nucles is less than the sum of the masses of its constituent nucleons. When you fuse two light elements into a heavier element, the mass difference appears in the form of energy.
Now, my question is this: why is a heavy nucleus less massive than the sum of the masses of the individual nucleons? I understand there’s something called “binding energy” that comes into play here, but here’s where I get lost. The term “binding energy” seems to imply that a heavier nucleus takes more energy to hold together than a lighter nucleus, but then this leads to a contradiction in my mind - if a heaver nucleus takes more energy to hold together, how could you ever gain energy by taking two light nuclei and adding energy to fuse them into a heavier one. Clearly, I’m missing something here.

Anyone wanna help me out?

If you want to bring two protons together, you have to use an external energy source to get them within one trillionth of a meter before the strong nuclear force will fuse them together and overcome the repulsion of two positive charges. The binding energy to fuse them together comes from the total mass, about 0.7% for hydrogen transforming to helium, for example. The energy used to trigger the fusion is less than the energy that is released as a result of the two protons coming close enough together to be fused and having part of their mass released by being converted to energy.

Get **Stranger ** in here and it will seem simple.

Isaac Asimov wrote an essay called “The Dead-End Middle” about Iron-56, which represents to most relaxed state matter can take. Anything lighter can be fused and release energy while anything heavier can be fissioned, though it’s only practical for the extremes - the lightest element (Hydrogen) and the heaviest (Uranium, or artificially-created heavier elements),

It should be easy to find a copy of Asimov’s essay collection “The Relativity of Wrong”. In addition to “Middle”, it has interesting essays on a variety of subjects and I recommend checking it and his other collections out the next time you’re in a used bookstore.

In simple terms when two protons are located some distance from each other, the system comprised of these particles has a certain potential energy. When they fuse (put together via a force and QM tunneling) that potential energy is converted to kinetic and electromagnetic energy.

At the same time the binding energy increases, but this isn’t a contradiction because Binding energy is negative.

Please don’t correct me - I’m simplifying.

And by the way mass isn’t converted to energy in this process; One form of energy is simply converted to another form. In fact the system mass remains the same and the local mass defect is the result of the energy loss not the source.

It’ll probably help to think of a nucleus as a battle between two different types of forces:

[ul]The strong nuclear force. Pulls individual nucleons (i.e. protons and/or neutrons) together, so is trying to hold the nucleus together.[/ul]
[ul]Electromagnetism. The protons are all postively charged, so electromagnetism is making them repel each other. Produces a tendency for the nucleus to fall to bits.[/ul]

Aside from their opposing tendencies, the two forces also differ in the way they act at different distances. The strong force between nucleons is very strong at short distances, but negligible once the two are any distance apart. Electromagnetism also falls off as you move protons apart, but much more slowly.

The balance of forces in a nucleus is thus different depending on the size of it. Think about adding a proton to a nucleus. The strong force is trying to make it stick, the electromagnetic force from the other protons is trying to repel it. But because the strong force only acts over short distances, the proton is really only “sticking” to those nucleons nearby. Any nucleons on the other side of the nucleus are too far away to help pull it in. That isn’t true of the electromagnetic repulsion from the other protons: they’re all contributing to push it away.
Thus the “pull” on the extra proton is about the same for all nuclei, but the “push” on it gets bigger the bigger the nucleus.

For small nuclei, the additional “pull” outweighs the additional “push” and so it’s energetically advantageous for them to get bigger. Our extra proton will stick. For large nuclei, the “push” starts to overwhelm the “pull” and it’s the other way round. There’s thus no contradiction.
It’s somewhere roughly about iron nuclei that there’s the crossover point.

Are you sure about this? The way I’ve heard it explained, ‘binding energy,’ ‘particle potential energy’, and so on are really expressed as extra mass compared to the other possible arrangements of the same subatomic particles. Even chemical reactions can convert mass to energy and back again, though the amounts of variation in mass is very small in those cases, maybe because it’s only the light electrons which are varying in mass in those situations.

Yes I’m sure. System mass is always conserved. To see this all you have to do is study Einstein’s relativistic equation that relates energy, mass and momentum

E[sup]2[/sup] = m[sup]2[/sup]c[sup]4[/sup] + p[sup]2[/sup]c[sup]2[/sup]

Or setting c = 1

E[sup]2[/sup] = m[sup]2[/sup] + p[sup]2[/sup] or

m[sup]2[/sup] = E[sup]2[/sup] - p[sup]2[/sup]

If there exists a frame where momentum (p) = 0 before the reaction then it must remain 0 after the reaction. Therefore:

m[sup]2[/sup] = E[sup]2[/sup] or m = E or E = mc[sup]2[/sup]

Since energy is conserved then so too is mass. (system mass)

Binding energy (which is negative) always increases as the nucleus size increases. However, the binding energy per nucleon does not necessarily increase. So, for instance, a single nucleus of Tellurium-112 would have more binding energy than a single nucleus of Iron-56. But that tellurium nucleus will have less binding energy, and hence more total energy, than two nuclei of Iron-56. So the tellurium nucleus can split into two iron nuclei, and release some energy in the process.

(Tellurium-112 isn’t actually naturally occuring, and if some were made artificially, it still probably wouldn’t fission into two irons. But that’s just because some other decay process would probably occur quicker. The fission would still be a possible, albeit likely, outcome.)

So… mass is not being converted into energy because energy IS ‘system mass’?? That seems more than a little misleading to me.

Mass and energy aren’t things; they’re properties of a system.

Mass is the magnitude of the energy momentum four vector and energy is its time component. More simply mass is energy that can’t be transformed away.

A photon does not have mass.

A system of two photons that have a center of momentum frame has mass.

A system consisting of a photon and a pipe has more mass then just the mass of the pipe.

A vault weighs the same both before and after a nuclear explosion occurs inside.

I don’t know if I can contribute more content than has already been added, much less make a simple explanation of the question, but I’ll try not to muddy the waters too much in an attempt to render a different, if not qualitatively more coherent, picture.

Before we go into binding energies and gluons and quantum chromodynamics and all that huff, let’s talk about mass first, because I’m guessing that what you think of as “mass” is not what mass really is, at least not on a fundamental scale. Mass–and by this I am referring to invariant mass, a.k.a. rest mass, a.k.a. ‘real’ mass, or also what strict pedants like to call “the only farking type of mass there really is”–is an invariant property of fundamental particles like electrons and quarks. Per particle, this is an absolutely known property that doesn’t go up or down, however much you may shake it or shine a light on it. We make not know where our eletrons are or what they’re about, but by Og we know what their charge, spin, and mass are.

Now, mass is a type of energy, per Einstein’s well known mass equivilence relation, E=mc[sup]2[/sup] (though it was actually Henri Poincaré who first established the relation, though he didn’t realize the full significance of it), but it’s a very special type of energy, bound up in a field that gives it the property of inertia, or resistance to a change in motion. In a sense, you can say that this inertia is conservative, because (apart from interactions with complementary antimatter particles) this invariant mass never changes, though obviously its momentum–the qualitative vectoral measure of its relative inertia, or more simply, how hard it is to slow down or change direction relative to a frame of motion–can change significantly. In other words, mass is a way to store, or at least localize, kinetic energy.

How do you measure momemtum? In basic terms, you let an object hit a known mass at a known velocity and measure the change. Since momentum of the total system is conserved (even if kinetic energy isn’t, in the case of an inelastic collision) you can deduce what the momentum of the original object was. The thing is, there are particles we know to be massless (or at least lacking invariant mass) like the photon, which also display the characteristic of momentum. So, while only some things have mass, everything has momentum. The thing about a photon, however, is that you can’t add to its velocity, or for that matter slow it down. Photons (and other massless particles, as far as we know and theory allows) all move at c, also known (somewhat tautologically) as the speed of light. If you try to slow a photon down, it just gets dimmer/has a lower frequency/longer wavelength. (It’s actually even more complicated than that, but we don’t want to mix with any quantum electrodynamics at this point.)

So a massy system in motion has momentum, but so do energetic systems without (invariant) mass. Make sense so far? In other words, all energy can be measured in terms of its contribution toward momentum. Mass, on the other hand, can only be measured directly in terms of the gravitational field it creates. Since its really, really difficult to measure the gravity field of small objects, we tend to conflate an object’s momentum with its mass. (You try weighing a helium atom on a scale.)

What does all of this have to do with to do with binding energies? Binding energy, as several others have already noted, is negative; that is to say, it is the opposite of potential energy, or more to the point, it represents the realized potential of the ground state of an unbound particle from its combined state. A cat sitting on the kitchen table has a ground state–well, a “table state”–of so-and-so many joules, based upon what it masses and how high the table is. If we arbitrarily make this the unbound state of the cat, then when it is pushed to the floor it is now reduced to a negative “bound” state based upon the mass of the cat and the height of the table. (The cat will let you know just how negative by the dirty look it gives you as it stalks off in anger.) The entire system will suffer an “energy defect”–a loss of potential energy–by the acoustic energy lost from the sound of the cat’s paws hitting the floor (and the yowl the cat makes at being displaced) but the defect is vanishingly small and will be reabsorbed by the air and walls to be converted into randomized thermal energy, so in a closed system the total amount of energy remains constant. The energy defect can also be seen in the now reduced gravitational field; since the field is more localized it appears “less massive”, although the effect is again, imeasurably small. In much more massive systems the adjoining of two masses results in significant loss of potential via gravitational radiation, but the invariant mass of the system is always constant.

Note that the interchange of energy comes about by interplay of two different and opposing forces; in this case, the graviational force which is attractive, and the electrostatic forces that make the cat, table, and floor appear to be solid. It’s not always obvious, but all “reactions” occur from the opposition of two opposed fields. (This is why (missing) dark matter–which only interacts gravitationally and very weakly via the “weak” nuclear force–doesn’t “clump” together the way normal baryonic matter does; it can’t slow down enough to form concentrations.)

We’re talking about gravitational binding energies here, of course (and making some arbitary definitions of ground for the sake of illustration and feline amusement) but a similar effect occurs with the atomic binding energies that come to play in nuclear fusion. In this case, of course, the binding energy is measured as the negative potential of the nuclear force or residual strong force, which wants to pull things together, albeit on a very short scale, versus the electrostatic force of charged nucleons (protons, unless you want to get all crazy and exotic), which try to push the nucleus apart, at least in anything more advanced than isotopes of hydrogen. The balance between these forces is the ground state of the hydrogen nucleus which has less energy than an individual proton and neutron.

This “mass defect”–actually a reduction in momentum–affects the probabilistic quantum behavior of the nucleons, but doesn’t change their invariant mass one whisker. If they were unbound, they’d appear to reign over a much larger area, but collectively they’re more localized, and the amount of energy in the system that is free to go into kinetic energy–rather than vibrational modes or interactions between the nucleons or however you wish to characterize it–is less. Where is the binding energy stored? It’s stored in connections between the nucleons; in QCD terms, it’s the energy transferred by the “virtual” gluons that are exchanged between nucleons that causes them to stick together, and once you prise them apart, the gluons–being incapable of existing in a deconfined, independent state–vanish in a puff of photons or energy applied to the now escaping nucleons, kind of like when an elastic bracelet snaps and sends beads flying all over. Does that sound like voodoo? Well, complain to Murray Gell-Mann; QCD is his baby, and I’ll be damned if I can really figure out what it all means anyway. It’s like a thoroughly rotton onion; the more layers you peel back, the gooeyer and less substantial it gets.

As previously noted, adding more nucleons does not proportionally increase (or rather, decrease) the binding energies; the difference between the two orginal states and the final state is released, in some form, as energy; either photons, or neutrinos, or surplus neutrons with a big bunch of kinetic energy. The total amount of energy released tends to drop as the reactants become more massive (though not strictly so, especially not on the very low end of the periodic table) but once you get up to iron there’s no more energy to be extracted, and you have to push with extra force just to get more energy. High level elements are stable, but only within a vary narrow “valley of stability”, outside of which they tend to decay spontaneously.

I started to write a lot more about fusion, Coulomb barriers, statistical mechanics and Maxwell-Boltzmann distributions, and quantum electrodynamics (which is a theory I can at least get behind and be confidently stupid about) but I realized that this didn’t really contribute anything to the o.p.'s question, the answer to which I’m hoping not to have completely obfuscated and diverged to extensively from at this point.

Stranger