# Numbers

If you add two even numbers the answer is a even number.
If you add two odd numbers the answer is a even number.
If you add a even number and a odd number the answer is a odd number.

As there is two ways of getting a even number, and one for getting a odd number, why isnt there twice as many even number as odd numbers?

If you multiply a number by two, you get an even number.

If you multiply a number by two and add 1, you get an odd number.

There is one way for each.

There are many ways to get a certain number.

Perhaps:

even + even = even
odd + odd = even
even + odd = odd
odd + even = odd

It all, ahem, evens out.

There’s always another beer.

Multiplying by two:
Even + Even= Even
Multiplying by two and adding 1:
Even + Even = Even + Odd (1)=, You still have to add a even and a odd number.

Perhaps:
EVEN + even = even
even + EVEN = even
ODD + odd = even
odd + Odd = even
even + odd = odd
odd + even = odd

Still twice as many ways of making a even number.

I find it, ahem, rather odd .

Nidd: are you prepared for a lengthy discussion of infinity, infinites, and transcendental numbers?

Let me know and if you are, I’ll give you an answer to your OP.

The equation is x + y = z.

x may be either even or odd.

y may be either even or odd.

Combinations possible are:

Evenx + Eveny = Even

Evenx + Oddy = Odd

Oddx + Eveny = Odd

Oddx + Oddy = Odd

Thus, of the four possible combinations, two result in odd answers, two result in even answers.

Of course, another way to answer this is: Yes, there ARE twice as many even numbers as there are odd numbers–there’s an infinite number of both, and twice (or half) an infinite number is still infinite.

Come again?

I have as much authority as the Pope; I just don’t have as many people who believe it! - George Carlin

I read a book when I was young called Billy(or bobby)and the Number Line. It was about the war between the even and odd numbers. The evens thought they were better,so the odds decided to jump on the evens;they immediately became odd(add and odd to and even,you get odd.) It was so cool.

The problem is in defining the question. The parameters given of what may be added skews the results to favor even.  If you allow
each element in the addition to be random, the result will be a 50% chance of odd or even. A chart is always truthful…

<table BORDER COLS=3 WIDTH=“53%” >
<tr>
<td>
<center>+</center>
</td>

<td>
<div align=right>First number</div>
</td>

<td>    </td>
</tr>

<tr>
<td>
<center>Second Number</center>
</td>

<td><font size=+1>Odd</font></td>

<td><font size=+1>Even</font></td>
</tr>

<tr>
<td>
<div align=right><font size=+1>Odd</font></div>
</td>

<td>Even</td>

<td>Odd</td>
</tr>

<tr>
<td>
<div align=right><font size=+1>Even</font></div>
</td>

<td>Odd</td>

<td>Even</td>
</tr>
</table>

Peace.