This is a game on Price is Right where a contestant gets some chips, big round things, and drops them down to 100$, 500$, 1,000$, 10,000$ or 0.
The zero’s are right next to the 10,000, which is in the midle.
What are the odds of a contestant getting the 10,000$ in the first drop?
Two drops?
It’s strictly a game of chance, so if there are 10 slots, the chance is 10% For two hits, it would be 1% (10% * 10%)
It’s not that simple, Mjollnir. It is strictly a game of chance, but the odds are not evenly distributed.
If you drop the chip from directly above the $10,000 slot in the middle, you are basically taking a random walk with N number of steps. N here is the number of steps down the Plinko board the chip has to maneuver (the pins, if you take my meaning).
A random walk can probably be defined much better by someone else, but I’ll give it a shot. For each step, you have a 50/50 chance of going left or right. The law of averages says that you should expect to land right back in the middle (about half your results being LEFT, half being RIGHT).
To fully answer the question, we’ll need to know how many steps a Plinko chip takes each trip, and how many slots there are at the bottom. I seem to recall that there are an odd number of slots (as it is symmetrical, but with only one $10,000 slot). However, without that information, we can’t really figure it out.
The only thing we do know is that if the odds of each result is truly 50% with no bias, there will be a normal distribution of results in the slots (i.e. the “bell” curve), with the $10,000 slot being the mode (all the while assuming that you’re dropping the chip directly above the $10,000 slot).
Tell us the number of slots, the number of steps, and we’ll be able to give you a fairly concrete answer.
Wow, what a wonderful link.
Thanks!
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