Whenever you ask “What are the odds of this?”, you have to specify exactly what “this” is. Getting five $1s on those particular five spins? I think the wheel has 20 spaces on it, so that’d be 1/20^5, or 1 in 3.2 million. But when you ask “What are the odds that five spins in a row would all come up $1, at any time in the show’s history?”, then the odds aren’t nearly so long, perhaps somewhere in the vicinity of one in several hundred (I’m not exactly sure how long the show has run, or how many spins they make per day). And if you extend “this” even further, to include similarly-remarkable events on other game shows, it becomes much more likely yet.
There are 20 slots (one each for values of $.05-1 in .05 increments). Only one $1 space. But it isn’t truly random, since the player spins the wheel as hard or soft as they want (provided the wheel makes at least one full turn) and combinations of two numbers which add to $1 count too.
I think it happened this past week, the first week of the new season. And yes, Drew looked a little more … padded.
There are 20 slots marked $.05 – $1.
$1 wins automatically.
2 spins totaling $1 also win.
So in one spin, a player has a 5% chance of winning.
Assuming he doesn’t get $1, he has a 5% chance of winning on his second spin.
A-a-a-a-and that’s as far as I can go. I know the total odds of one person winning once isn’t 0.5 x 0.5 = 0.25 = 2.5% (because if you win the first time, you don’t spin the second time (I think that matters, right?)), but I don’t know what it is.
Do we need to look at two spins as one event with 20 x 20 = 400 possible outcomes? Or 380, since you don’t spin twice if you get $1 the first time. There are 11 favorable outcomes (1, .05/.95, .10/.90 … .45/.55, .50/$.50). So the odds are 11/380, which is roughly a 2.9% chance of winning. As for that happening five times in a row, I don’t know.
I realize I could be way off base on this — high school math was a long time ago. I’d really be interested in having someone explain.
(And to keep Chronos happy, let’s say “on those five attempts,” not “at any point in the run of the show.”)
(Is “on any given five consecutive attempts” the same as “on those five attempts”?)
You do know that they select contestants based on how excited and energetic they seem, right? So it’s not really a surprise to see a guy going crazy on stage like that.
The odds that all three contestants roll a dollar on their first spin(s) is 1 in 1079. This assumes that the first contestant will spin the wheel twice if (s)he doesn’t hit a dollar on the first spin, which isn’t realistic, because (s)he would stop if they spun a pretty high number.
Chance of NOT rolling a dollar on first spin: .95
Chance of NOT rolling a dollar on second spin: .95
Chance of NOT rolling a dollar on either spin: .95 x .95 = .9025
Chance of contestant rolling a dollar: 1 - .9025 = .0975
Chance of all three contestants rolling a dollar: .0975^3 = .000927
.000927 is 1 in 1079
Chance of NOT rolling a dollar on bonus spin: .95
Chance of all 3 contestants NOT rollling a dollar on their bonus spin: .95^3 = .857
Chance of at least one contestant rolling a dollar on bonus spin: 1 - .857 = .143
Chance of all three contestants rolling a dollar AND at least one contestant rolling a dollar on bonus spin: .000927 x .143 = .000132
.000132 is 1 in 7565
Chance of rolling a dollar on bonus spin: .05
Chance of all three contestants rolling a dollar on bonus spin: .05^3 = .000125
Chance of all three contestants rolling a dollar AND rolling a dollar on bonus spin: .000927 x .000125 = .000000116
.000000116 is 1 in 8.6 million
I don’t know how to calculate 2 contestants rolling dollars on their bonus spins, but it’s somewhere between 1 in 7265 and 1 in 8.6 million.
Note: Numbers have been rounded in text, but not in calculations.
Also remember, this event actually happened so the real odds of it happening are 100%. There are millions of “What are the odds?” events that can happen on a game like The Price Is Right, so if the game gets played as many times as it has, some unlikely events will occur. The real challenge is predicting a long odds event BEFORE it happens.
I’m not sure I would use the word “odds” in that case. To me, the word only really make sense referring to the probability prior to an observation.
Now that could be the next layer of the question. Given how many wheel spins there have bin in the show’s history, what was the probability that 5 dollar-totaling spins in a row would have occurred at some point during the show’s run.
Well, if you’re counting “in a row” as part of it, I’m getting a number of 1 in 430-450K (using your intial numbers), depending on whether you want to throw out the case where the last guy also gets a dollar on his spin.
There have been ~10,000 episodes, with 2 Big Wheel segments each, since the current format began in 1972.
So, that’s around 20k chances for all three initial spins to hit the dollar. This has happened a dozen or so times. Which fits with my quick back of the envelope calculation as to how often that would happen.
Since 5-dollar-space rounds are necessarily a relatively rare subset of the 3-dollar-space starters, and we’re excluding ones where the first or second contestant is the one who misses the second dollar, we’re a rather long way from the point where the number of trials multiplied by the probability of it happening approaches 1.