This is a simple binomial problem with n=4, p=1/6. For exactly one instance that the dice will be a 7 the probability is .3858. For 1 or more instances, it’s .4823.

Did I mention I suck at math? I just want to make sure I understand your answer…

If the “probability is .3858”, that means that 38.58 times out of a hundred, I can expect the result in question?

Or in other words, in four roles I’m likely to see one and only one 7 a little more than a third of the time, and two or more sevens almost half the time?

The probabllity that you WON’T get a 7 in one roll is 5/6. The probability that it won’t happen four times in a row is (5/6)^4 which is 625/1296 or about 48.2% and the probability you will is 51.8%.