Inspired by this thread, but I want to talk about math theory, not practice. (Ice-cube tray question… )
I once had the perfect ice cube trays, and have never seen them again, but would like to define them.
(Please assume for discussion that “cube” refers to any chunk of ice, not strictly cubical in shape.)
The key to the perfect ice cube tray is that as the ice forms the cubes expand:
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a worst case tray would have perfectly square slots, and the ice would wedge itself from side to side, locking in solidly.
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a V-shaped trough or point-down cone would at first appear to produce easily-freed cubes, but this is not the case. As the cubes expand, they simply slide to new positions along the shape, and there is full contact between the cube and the walls.
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A parabolic slot would seem ideal, since although increasing the size of a parabola leaves it “the same shape”, it really only makes contact with its old shape at the top edges, thus being essentially free. Of course, since it is sealed at all times at the top edge, the gap forming beneath the cube is a vacuum, now forcing the ice to again become hard to budge, although only the edge seal must be broken, not the entire bottom and side walls.
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I believe that a quadratic curve would have the same effect (one that looks like a barrel half, but with a bulge rather than a flat bottom)
Now, for the shape of these lost perfect trays - They were parabolic from port to starboard, if you will, and quadratic from fore to aft.
The result was that as the ice formed the cube would expand and rise out of the slot, but since the expansion in one direction was greater than the other direction, no seal would form at the rim and the cube would be free, resting on only two points of the rim.
I’m sure this shape was accidental, although I wonder whether some unsung genius had a long overlooked and now expired patent on the perfect shape.
Is this analysis correct? I.e., would it really work? Or have I misremembered the whole thing?