No, this isn’t homework and no, you aren’t helping me figure out my / my friends grades. I’ve seen this done a lot in college classes, and am just curious how an instructor makes these calculations.
Let’s say a college student is taking some random class, with the grading as follows:
Notebook/journal keeping: 10%
Research paper: 20%
Midterm: 30%
Final: 30%
Class attendance/ group discussion 10%
So, at the end of the term but BEFORE the final and notebooks are graded this student has, say, a 90% overall in the class. So, 60% of the work done so far has earned him/her a 90%.
Let’s say that the notebook is crap and gets a 0% and the final test earns, say an 85%.
What’s the formula to figure out what the final grade (%) will be? What if the notebook grade changes to a 25% or 50% or whatever%, or the final test grade changes?
85% of 30 is 25.5 points, added to the 54% is 79.5%.
25% of 10 is 2.5 points. 50% would be 5 points. Add that to the 79.5%.
Each component’s grade is multiplied by the points for each component. (Getting a 76% on the final would get you 76%*30 = 22.8). Then just add them up.
So apparently you’re claiming that the research paper (20%), the midterm (30%), and class attendance/group discussion (10%) are collectively at a 90 out of a 100 level. This says that 60% of the grade is at a 90 out of 100 level. You’re also saying that the notebook (10%) is at a 0 out of 100 level and the final (30%) is a a 85 out of 100 level. So then the following equation should give us the overall grade (100%):
(60% times 90) + (10% times 0) + (30% times 85) = 100% times (Overall Grade)
That reduces to this:
(.6 times 90) + (.1 times 0) + (.3 times 85) = 1 times (Overall Grade)