How Can You Get Four Outs in Baseball (in half an inning)

I did a search here, but came up with nothing.

The story is, I read once, that while 3 outs normally retires the side, there were circumstances where 4 outs could actually be scored. I can not for the life of me remember the details of how that could happen.

Any baseball gurus out there who can enlighten me, or am I just “misremembering” what I read?

When a batter strikes out and the ball is not caught by the catcher, the batter can run to first base will need to be put out by the defence (tagged out or ball thrown to first). If the runner makes it to first, he remains there and a strikeout is credited to the pitcher, but the defense still needs three other outs to complete the half inning.

What you might also be thinking of is a pitcher getting 4 strikeouts in a half-inning. It’s been done many times!

Sorry for the poor sentence structure and spelling. I’m calling it a day.

Runners at 3rd and 1st with 1 out.

Batter hits fly ball and both runners take off.

Ball is caught (out #2). Runner on 3rd crosses home plate.

Ball is thrown to 1st to double off that runner (out #3).

[If, at this point, the defence leaves the field, the run will count.]

Ball is thrown to pitcher on mound, an appeal play is made to 3rd base (out #4). Run does not count.

(Very theoretically, with bases loaded and no outs, you could have a 5 out inning.)

This “4th out” situation occured about 10+ years ago once. But the defence left the field. The home plate umpire after the game went to both locker rooms to inform the managers of the actual score of the game. (The scoreboard had not recorded the run.) Why this wasn’t fixed by the start of the next inning is beyond me.

You can get this with an appeal play.

Suppose a runner is on second base with two outs. The batter hits a long double; the guy on second scores. The batter tries to take third base, but is tagged there for the third out. Very straightforward.

Now, suppose the team in the field makes an appeal throw to third base - they’re claiming the guy on second failed to touch third base on his way home. The umpire saw this failure, and so signals that the baserunner is out, and the apparent run he scored doesn’t count. Thus you have a half-inning with four outs.

Oops: Very theoretically … bases loaded and 1 out.

Rats - thrown out by ftg while sliding home.

How about 6?

Two outs, bases loaded. Batter hits a long double - all guys on base appear to score. Batter is eventually caught in a rundown and finally tagged out trying to get back to second base. Three outs.

But it then turns out that the guy on third failed to touch home plate, and both the other baserunners missed third base. Sufficient appeal throws are made. Do we not end up with 6 outs?

Just four outs. Once the appeal play is made on the runner on the plate the inning is over and no runs score.

Here I was looking for what I thought was one unique situation, and you all come up with all these scenarios.

All I can do is quote Ray Romano’s father and say “Holy Crap”…you are all GOOD.

Thanks and please keep 'em coming if there are other situations. Didn’t want to shut down this thread, just wanted to acknowledge one & all. :slight_smile:

Makes sense.

But suppose the appeal at third is done before the one at home plate?

Here’s the end of Rule 7.11 which will no doubt “clarify” the matter: