- [symbol]Ñ[/symbol] x H = [symbol]e[/symbol][sub]0[/sub] [symbol]d[/symbol]E/[symbol]d[/symbol]t + j
- [symbol]Ñ[/symbol] x E = - [symbol]m[/symbol][sub]0[/sub] [symbol]d[/symbol]H/[symbol]d[/symbol]t
- [symbol]Ñ[/symbol] . H = 0
- [symbol]Ñ[/symbol] . E = [symbol]r[/symbol]/[symbol]e[/symbol][sub]0[/sub]
God said…
and there was light…
I can only assume that’s Maxwell’s Equations. Pretty cool, but FYI, it won’t look like that to everyone. I use Netscape, and here’s how it looks to me:
Try this:
- [symbol]Ñ[/symbol] x H = ε[sub]0[/sub] ∂E/∂t + j
- [symbol]Ñ[/symbol] x E = - μ[sub]0[/sub] ∂H/∂t
- [symbol]Ñ[/symbol] . H = 0
- [symbol]Ñ[/symbol] . E = ρ/ε[sub]0[/sub]
How does that look in Netscape? And anyone know another way to do the del operator?
ƒ
I’d thought Symbol was pretty much universal…
Ah well
Grim
To do a del operator in Netscape you can use:
∇ = ∇
But I don’t think is universal, either.
That shows up as a square in IE.
How was the rest of my post? Did rho, epsilon, mu and the partial differential show up correctly?
Yes they did. Although the dot product looked like a period.
test
tests:
:B
:E
:o
:mad:
:smack:
And for some reason, your B for the magnetic field came out looking like an H, and we all know that’s not right. After all, it’s all vacuum anyway.
<d&r>
You might also try, by the way, just using a superscript period for a dot product. It won’t copy and paste well, but it will at least look right on (almost) all browsers.
I think that just using · will work too. Let’s see:
A · B
D = ε[sub]o[/sub]E + P
H = B/μ[sub]o[/sub] − M
[symbol]Ñ[/symbol] x H = ∂D/∂t + J
[symbol]Ñ[/symbol] x E = − ∂B/∂t
[symbol]Ñ[/symbol] · B = 0
[symbol]Ñ[/symbol] · D = ρ
Happy with that version, Chronos?
And if it was free space, I could write:
[symbol]Ñ[/symbol][sup]2[/sup] x B = μ[sub]o[/sub]ε[sub]o[/sub] ∂[sup]2[/sup]B/∂t[sup]2[/sup]
[symbol]Ñ[/symbol][sup]2[/sup] x E = μ[sub]o[/sub]ε[sub]o[/sub] ∂[sup]2[/sup]E/∂t[sup]2[/sup]
Alternatively, in Heaviside-Lorentz:
D = E + P
H = B − M
[symbol]Ñ[/symbol] x H = (∂D/∂t + J)/c
[symbol]Ñ[/symbol] x E = (-∂B/∂t)/c
[symbol]Ñ[/symbol] · B = 0
[symbol]Ñ[/symbol] · D = ρ
May as well do the others, too.
Gaussian:
D = E + 4[symbol]p[/symbol]P
H = B − 4[symbol]p[/symbol]M
[symbol]Ñ[/symbol] x H = (∂D/∂t + 4[symbol]p[/symbol]J)/c
[symbol]Ñ[/symbol] x E = (-∂B/∂t)/c
[symbol]Ñ[/symbol] · B = 0
[symbol]Ñ[/symbol] · D = 4[symbol]p[/symbol]ρ
cgs esu:
D = E + 4[symbol]p[/symbol]P
H = c[sup]2[/sup]B − 4[symbol]p[/symbol]M
[symbol]Ñ[/symbol] x H = ∂D/∂t + 4[symbol]p[/symbol]J
[symbol]Ñ[/symbol] x E = -∂B/∂t
[symbol]Ñ[/symbol] · B = 0
[symbol]Ñ[/symbol] · D = 4[symbol]p[/symbol]ρ
And, lastly, cgs emu:
D = E/c[sup]2[/sup] + 4[symbol]p[/symbol]P
H = B − 4[symbol]p[/symbol]M
[symbol]Ñ[/symbol] x H = ∂D/∂t + 4[symbol]p[/symbol]J
[symbol]Ñ[/symbol] x E = -∂B/∂t
[symbol]Ñ[/symbol] · B = 0
[symbol]Ñ[/symbol] · D = 4[symbol]p[/symbol]ρ
Buncha fuggin’ geeks.