HERE IT GOES:-
A pet shop had a puppy sale. 2 men entered. The first man put down $10 and the assistant asked for which type of puppy he wanted, an alsation, labrodor or poodle, He choose the poodle. The second guy put down $10 and without uttering a word the shop assisant simply gave him an alsation.
They were having a special on ONLY alsations, labradors, and poodles. The shop was out of labs and only had one poodle. When the first guy took the last poodle, the clerk gave the second guy an alsation because that’s all he had left.
Maybe the second guy was wearing an “I (heart) alsations” shirt.
The job that Alsatians genrally do that Labradors generally don’t is acting as guard dogs, so perhaps something told the shop assistant that the man needed a guard dog?
Another possibilty could be that the sale on puppies ended inbetween the time that the first and second man bought there dogs.
Howver I think the most likely answer is that the dogs were differently priced, for example $10 for the Alsatian $9 for the poodle and $8 for the Labrador. The first man could of given the shop assistant a $10 bill, whereas the second could of given the shop assistant a $5 bill and 5 $1 coins.
Well, it wasn’t stated that they paid with $10 bills or whether the puppies were the same price or whether they got change. If your sister stated any of these things then it’s not a solution, but remember that most riddles try to make you make assumptions.
I have seen this riddle before, and this is the correct answer. Here’s the reasoning:
(We correctly ignore any discussion of whether each man got change or not, because the riddle does not mention it. We must go on only what was stated in the problem.)
A person who puts down a $10 bill could be expecting to buy any one of the three kinds of dogs, and be expecting change for those that are less than $10.
But a person who puts down a $5 bill and five $1 bills clearly intends to buy the $10 dog. If he wanted a $9 dog he would have put down a $5 and four ones. Same for the $8 dog, only a $5 and three ones.
(Of course, this is all according to the logic of Puzzle-Land. A polite and conscientious clerk in Real Life will still ask and not assume anything, in case the customer miscounted the bills or something.)
No – they are different prices, just as MC said. That is one of the parts of the riddle that you must figure out in order to solve it. Nowhere in the riddle does it SAY that they are all $10. It just says that each man put down ten dollars. The two things you must figure out are:
(1) The dogs are different prices.
(2) Each man put down different denominations of bills.
So correct me if I’m wrong:-
The first guy put down a $10 bill and he got to choose what he wanted, but the 2nd guy put down $5 and 5 1 dollar coins, expecting no change - because the alsation cost $10 exactly!
I think so, but I’m not sure. See if this aligns with how you are seeing it:
What you need to look at is each customers CHOICE OF BILLS that they put down.
The first guy put down a $10. This could mean that it’s all he had, or maybe he had the correct change but wanted a few extra bills, or just grabbed whatever came out of his wallet. We can make no assumptions about how much he intends to spend based on the bill that he put down.
But the second guy put down a $5 and five $1s. This is interpreted as a deliberate act saying that he wants the $10 dog. If he wanted the $9 dog he would not count out a $5 and five $1s; he would put down a $5 and four $1s. Same for the $8 dog; he would put down a $5 and three $1s.
As another example, you wouldn’t stand at a counter and count out 25 pennies if you wanted to buy a piece of candy that cost 20 cents; you must want something that costs 25 cents.