Hey everyone,
I swear to Og that this thread has a factual answer. Ok, basically, in my park there are many squirrels. These squirrels are laughing at me, so I wish to make them pay for this outrage. kidding!
In any case, I want to make a little mischief for these squirrels without hurting them. I’m thinking a supersoaker (water gun) would be perfect for this.
I am wondering if I can successfully shoot one and get it a little wet, or if it instead scampers away too fast?
The variables involved in this question that I believe give it a factual answer:
Distance from me to aforementioned squirrel= Dt
Speed of supersoaker water stream = Sw (dependeant on Psi of water tank and model of gun probably)
Speed of squirrel = Ss
Reaction speed of squirrel = Rs
So. Distance = Rate x Time, so Time = Distance / Speed? I’m always bad at that part. Well, I think that if Dt/Sw < Dt/ Ss+Rs then vengeance shall be mine!
That’s what they get for throwing nuts at me :mad: Not kidding on that one…
Park squirrels are usually inured to the human presence. If you can catch one close to you, that’s looking the other way, you’ve a good chance of getting the drop on him. Check with the park department, though. They may have rules against hassling the wildlife.
Their definition of harmless fun could be different from yours.
Why would your idea of a good time be to harrass animals? Surely there are a couple of tens of thousands of other hobbies you might take up that don’t involve molesting other creatures.
Catapulting the squirrel about fifty yards and then laughing about it? Seriously, laws prevent us from doing this shit to each other, but the need is there - humans, absolutely, under no circumstances, can ever, stop being retards 100% of the time. We wouldn’t discover anything that way.
And note that being launched by a trebuchet is unlikely to hurt the squirrel. I’ve frequently seen squirrels fall from tall trees and scamper off when they hit the ground.